Question 86383
2/sqrt[3] + sqrt[2]
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Multiply numerator and denominator by (sqrt3 - sqrt2) to get:
[2(sqrt3 - sqrt2)]/[3-2]
=2(sqrt3 - sqrt2)
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Why does this work?
Because (sqrt3+sqrt2)(sqrt3-sqrt2) = 3+sqrt6-sqrt6-2 = 3-2=1
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Cheers,
Stan H.