Question 1009386

let bigger number be {{{x}}} and smaller number {{{y}}}

if the sum of numbers is {{{260}}}, we have

{{{x+y=260}}}.........eq.1

if one number is {{{9}}} times as big as the other,we have

{{{x=9y}}}..........eq.2 substitute it in eq.1

{{{9y+y=260}}}.........eq.1...solve for {{{y}}}

{{{10y=260}}}

{{{y=260/10}}}

{{{highlight(y=26)}}}->the smaller number

then,
{{{x=9y}}}..........eq.2
{{{x=9*26}}}
{{{highlight(x=234)}}}->the bigger number