Question 1009363
factor:8x^3-27 
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The form is "the difference of cubes".
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(2x)^3 - 3^3 = (2x-3)((2x)^2 + 2x*3 + 3^2) 
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= (2x-3)(4x^2 + 6x + 9)
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Cheers,
Stan H.
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