Question 1009348
it is already written as sum or difference; you probably need to write it as a single logarithm


{{{log((5c^4+8c))+log((c^-1))}}}

{{{log(c(5c^3+8))+log((1/c))}}}

{{{log(c(5c^3+8)(1/c))}}}

{{{log(cross(c)(5c^3+8)(1/cross(c)))}}}

{{{log((5c^3+8))}}}



{{{(1/2)(10*ln((m-4)))+ln ((m))-ln (m^2)}}}


{{{(1/2)(ln((m-4)^10))+ln (m/m^2)}}}

{{{ln(((m-4)^10)^(1/2)))+ln (cross(m)1/m^cross(2))}}}

{{{ln((sqrt((m-4)^5)^2))+ln (1/m)}}}

{{{ln((m-4)^5))+ln ((1/m))}}}

{{{ln((m-4)^5(1/m))}}}

{{{ln((m-4)^5/m))}}}