<PRE><B>Question 1009301</B>
 Let theta be an angle in quadrant 2 such that sec theta=-5/4. Find the exact values of cot theta and sin theta.? 
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Note:: x is negative and y is positive in QII.
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By definition, sec(t) = r/x
So, r = 5 and x = -4.
Then y = sqrt[5^2-4^2] = sqrt(25-16) = sqrt(9) = 3
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Answers::
cot(t) = x/y = -4/3
sin(t) = y/r = 3/5
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Cheers,
Stan H.
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