Question 1009326
9x^2+9y^2-12x-6y-31=0 Transform the equation to standard form, then give the coordinates of the center and the radius.
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Complete the squares for x and y.  That's all it takes.
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You get {{{(x-h)^2 + (y-k)^2 = r^2}}}
(h,k) is the center, r = radius