Question 1009299
(sin^2x-tan^2x)/(tan^2xsin^2x) = 
(sin^2x/(tan^2xsin^2x)) - (tan^2x)/(tan^2xsin^2x)) = 
1/tan^2x - 1/sin^2x = 
cos^2x/sin^2x - 1/sin^2x =
(cos^2x - 1)/sin^2x = 
-sin^2x / sin^2x = 
-1