Question 1009249
It's a trick. Just express {{{ 1 }}} as a log.
In this case: {{{ 1 = log( 4,4 ) }}}
{{{ log( 4, ( 4x + 9 )) = log( 4,4 ) }}}
Then it follows:
{{{ 4x + 9 = 4 }}}
{{{ 4x = -5 }}}
{{{ x = -5/4 }}}
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Plug this back into original equation
{{{ log( 4, ( 4x + 9 )) = 1 }}}
{{{ log( 4, ( 4*(-5/4) + 9 )) = 1 }}}
{{{ log( 4, 4 ) = 1 }}}
{{{ 1 = 1 }}}
OK