Question 1009152
set f(x) equal to 0 and you get:


2x^2 - 16x + 30 = 0


factor out a 2 and you get:


2 * (x^2 - 8x + 15) = 0


factor x^2 - 8x + 15 to get:


2 * (x-3) * (x-5) = 0


set each of these factors equal to 0 to get:


x-3 = 0 and x-5 = 0


solve for x to get x = 3 and x = 5.


the zeroes of y = 2x^2 - 16x + 30 are at x = 3 and x = 5.


here's the graph:


<img src = "http://theo.x10hosting.com/2015/120906.jpg" alt="$$$" </>


your second equation is:


g(x)= x(x-3)^2 (x+1)^4 


set g(x) equal to 0 and you get:


x * (x-3)^2 * (x+1)^4 = 0


set each of these factors equal to 0 and you get:


x = 0 and (x-3)^2 = 0 and (x+1)^4 = 0


solve for x in each of these equations to get:


x = 0


(x-3)^2 = 0
take square root of both sides of this equation to get:
(x-3) = 0
solve for x to get x = 3


(x+1)^4 = 0
take the fourth root of both sides of this equation to get:
x + 1 = 0
solve for x to get x = -1


your zeroes are at x = -1, x = 0, and x = 3


here's the graph:


<img src = "http://theo.x10hosting.com/2015/120908.jpg" alt="$$$" </>