Question 1009159

Find three consecutive odd integers such that the product of the first and third is equal to 1 less than twice the second. 

It's quite a confusing problem to read, but I wasn't taught this in class because I recently moved schools.
<pre>Let the smallest be S
Then others are: S + 2, and S + 4
We then get: S(S + 4) = 2(S + 2) - 1
{{{S^2 + 4S = 2S + 4 - 1}}}
{{{S^2 + 4S - 2S - 4 + 1 = 0}}}
{{{S^2 + 2S - 3 = 0}}}
(S + 3)(S - 1) = 0                 
S, or smallest = {{{highlight_green(- 3)}}}        OR         {{{highlight_green(S = 1)}}}
You should be able to find the other 2