Question 1009174
Let


P = (6,6)
Q = (2,3)
R = (4,7)


Find the <a href = "http://www.algebra.com/algebra/homework/Linear-equations/slope.solver">slope</a> of segment PQ to get {{{3/4}}}


 
Find the <a href = "http://www.algebra.com/algebra/homework/Linear-equations/slope.solver">slope</a> of segment PR to get {{{-1/2}}} 



Find the <a href = "http://www.algebra.com/algebra/homework/Linear-equations/slope.solver">slope</a> of segment QR to get {{{2}}} 



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Multiply the slopes of PR and QR to get


(slope of PR)*(slope of QR) = (-1/2)*(2) = -1


Since the product of the two slopes is -1, this means that segment PR and segment QR are perpendicular. We have a right angle form at where the segments meet (at point R)


So we definitely have a right triangle.