Question 1009040


 If {{{y }}}is directly proportional to the {{{sqrt(x )}}}, we have 
{{{y =k*sqrt(x )}}}

and if {{{y = -32}}} when {{{x = 400}}}, we can find a constant {{{k}}}

{{{-32 =k*sqrt(400 )}}}

{{{-32 =k*20 }}}

{{{k= -32/20}}}

{{{k= -8/5}}}

so, equation is: {{{y = (-8/5)*sqrt(x )}}}

 if {{{x = 160000}}}, then

{{{y = (-8/5)*sqrt(160000 )}}}

{{{y = (-8/cross(5))*cross(400)80 }}}

{{{y = -8*80 }}}

{{{y = -640 }}}