Question 1009038
{{{ f(t) = (4)/(t^2) }}} Use the definition of the derivative to determine f'(-1)
{{{ f(t) = (4)/(t^2) = 4t^(-2) }}}
f'(t) = {{{-2*4t^(-3)}}}
f'(-1) = -8*(-1)^(-3)
= 8
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Let {{{ g(x) = 1/(x+1) }}} Use the definition of the derivative to determine g'(1) 
{{{ g(x) = 1/(x+1) }}}
{{{ g(x) = (x+1)^(-1) }}}
g'(x) = {{{-1*(x+1)^(-2)}}}
g'(-1) = {{{-1*2^(-2)}}}
= -1/4