<PRE><B>Question 1008954</B>
find the exact value of the indicated trigonometric function of 0 
sin 0=-4/7, tan 0 greater than 0 find sec 0 
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Note: If tan is positive and sin is negative, the angle is in QIII
where x is negative and y is negative.
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By definition, sin = y/r ; so y = -4 and r = 7
Then x = -sqrt[7^2-4^2] = -sqrt[33]
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Ans: sec(t) = r/x = -7/sqrt(33)
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Cheers,
Stan H.
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