Question 1008991
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8 - 8i = 8*(1-i).


1 - i has a polar angle {{{theta}}} = {{{2pi - pi/4}}} = {{{7pi/4}}} and the modulus of {{{sqrt(2)}}}.


Therefore, 8-8i = {{{8*sqrt(2)*(cos(7pi/4) + i*sin(7pi/4))}}}.