Question 1008841
We need to rationalize the denominator
{{{(3+4i) / (4+i)}}} =
{{{(3+4i)(4-i) / (4+i)(4-i)}}} =
{{{(12 - 3i + 16i - 4i^2) / (16 - i^2)}}} =
{{{(16 + 13i) / 17}}}