<PRE><B>Question 1008719</B>
serigo, jim, simone, maria and dawn have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a) in how many ways can they arrive?:: 5!
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b) in how many ways can sergio arrive first and dawn last?::1*1*3!
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c) find the probability that sergio will arrive first and dawn last?
# of ways to succeed:: 3! = 6
# of possible arrangements:: 5!
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Ans: 6/5! = 0.05
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Cheers,
Stan H.
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