Question 1008668
P(defective)=5/11
P(not_defective)=6/11
So, all defective,
{{{P=(5/11)(5/11)(5/11)(5/11)(5/11)=3125/161051}}}
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All not defective,
{{{P=(6/11)(6/11)(6/11)(6/11)(6/11)=7776/161051}}}
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