Question 1008541
Find three consecutive natural numbers if the square of the smallest number is 65 less than the product of the remaining two numbers. 
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1st:: x-1
2nd:: x
3rd:: x+1
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Equation:
(x-1)^2 = x(x+1)-65
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x^2 - 2x + 1 = x^2 + x - 65
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3x = 66
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x = 22
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x-1 = 21
x = 22
x+1 = 23
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Cheers,
Stan H.
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