Question 1008515
 ((5x)/(48y^2)) + ((7y)/(18x^2y)) 
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Prime-factor each denominator::
48y^2 = 3*(2^4)*y^2
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18x^2y = 3^2*2*x^2*y
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lcd = 3^2*2^4x^2y^2 = 9*16x^2y^2 = 144x^2y^2
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Rewrite each fraction with the lcd as it divisor::
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[3x^2*5x + 2^3*y*7y]/[144x^2*y^2]
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= [15x^3 + 56y^2]/[144x^2y^2]
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Cheers,
Stan H.
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