Question 86315
distance = (rate)(time)
her distance is the same coming and going
(rate)(time) for the trip out = (rate)(time) for the trip back
5x = 4(x + 5)
5x = 4x + 20
5x - 4x = 20
x = 20 MPH on the trip out
x + 5 = 20 + 5 = 25 MPH on the trip back