Question 86255
 write in the simplest form
y-2/y+3-y/2y+6=
:
Assume you mean:
{{{((y-2))/((y+3))}}} - {{{y/((2y+6))}}} = {{{((y-2))/((y+3))}}} - {{{y/(2(y+3))}}}
:
The common denominator would be: 2(y+3)
{{{(2(y-2) - y)/(2(y+3))}}} = {{{(2y - 4 - y)/(2(y+3))}}} = {{{(y - 4)/(2(y+3))}}} or {{{(y - 4)/(2y+6))}}}