Question 1008272
{{{system(x^2+y^2=106,x+y=-4)}}}


{{{y=-x-4}}}
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substitute this into the squares equation.
{{{x^2+(-x-4)^2=106}}}
{{{x^2+(-1)^2(x+4)^2=106}}}
{{{x^2+1*(x+4)^2=106}}}
{{{x^2+x^2+8x+16=106}}}
{{{2x^2+8x+16=106}}}
{{{x^2+4x+8=53}}}
{{{x^2+4x+8-53=0}}}
{{{x^2+4x-45=0}}}
{{{(x-5)(x+9)=0}}}


x can be either 5  or  -9.
Correspondingly,
y can be either -9 or 5.


The two numbers are  <b>5 and -9</b>
Because this will match the second part of the description: that the sum be NEGATIVE 4.