Question 1008121
So your question "what is the area and perimeter of a ice cream cone shape object when the width given is 6m and the length given is 6m?" is a bit vague but from my perspective do you mean "the width given" as "the diameter given" of the semi-circle and as "the base of the triangle given" is 6 meters and "the height given" as "the height given" of the triangle is 6 meters? Also do you mean this shape shown below? 

*[illustration Possible_diagram]

If yes then to find the area of a semi-circle: 

Firstly find the radius of the semi-circle {{{ radius = 0.5*6 = 3 }}} then sub 3 into the area of semi-circle formula {{{ A =(0.5*pi)*radius^2 }}} which looks like this {{{ A =(0.5*pi)*3^2 }}} which then equates to {{{ 1.570796327*9 }}} and finally {{{ A = 14.13716694m^2 }}}

Then to find the area of a triangle: 

Firstly sub both 6's into {{{ A = (0.5*base)*height }}} which looks like this {{{ A = (0.5*6)*6 }}} which equates to {{{ 3*6 }}} and finally {{{ A =18m^2 }}} 

Then find the sum of the area of a triangle and the area of a semi-circle:

{{{ A = 14.13716694m^2 + 18m^2 }}} which equates to  {{{ A = 32.13716694m^2 }}}



To find the perimeter first find the hypotenuse of the triangle:

first sub 3 and 6 into {{{ Hypotenuse^2 = base^2+height^2 }}} which looks like this {{{ Hypotenuse^2 = 3^2+6^2 }}} which equates to {{{ Hypotenuse = sqrt(45) }}} and finally {{{ Hypotenuse = 6.708203932m }}}

secondly find the arc of the semi-circle: 

first sub 6 into {{{ Arc  = (0.5pi)*diameter }}} which looks like this {{{ Arc  = (0.5pi)*6 }}} which equates to {{{ Arc  = 1.570796327*6 }}} and finally {{{ Arc  = 9.424777961m }}}

finally find the sum of the hypotenuses and the arc of the semi-circle to find the perimeter:

{{{ P  = (6.708203932*2)+9.424777961 }}} which equates to {{{ P = 22.84118582m }}}


Therefore the area of the cone is {{{ 32.13716694m^2 }}} and the perimeter of the cone is {{{ 22.84118582m }}}