Question 1008180

recall: {{{(a-b)^2=a^2-2ab+b^2}}}
a)
{{{x^2-(2/3)x+b^2}}}...............{{{2ab=2/3}}}=>since {{{a=1}}}, {{{2b=2/3}}}=>{{{b=2/(3*2)=1/3}}}

{{{x^2-(2/3)x+(1/3)^2}}}

{{{(x-1/3)^2}}}

b)

{{{x^2-px+b^2}}}.....{{{2ab=p}}}=>since {{{a=1}}}, {{{2b=p}}}=>{{{b=p/2}}}

{{{x^2-px+(p/2)^2}}}

{{{(x-p/2)^2}}}