Question 86286
{{{(y-2)/(y+3)}}} - {{{y/(2y+6)}}}
Determine the LCD of y + 3 and 2y + 6. Put the 2y + 6 in factored form:
{{{(y-2)/(y+3)}}} - {{{y/(2(y+3))}}}
The LCD is 2(y + 3)
Change each fraction to an equivalent fraction having a denominator of 2(y + 3):
{{{2(y - 2)/(2(y + 3))}}} - {{{y/(2(y+3))}}}
Distribute:
{{{(2y - 4)/(2(y + 3))}}} - {{{y/(2(y+3))}}}
Combine the numerators:
{{{(2y - 4)/(2(y + 3))}}} - {{{y/(2(y+3))}}} =
{{{(y - 4)/(2(y + 3))}}}