Question 86293
{{{(2x-6)/21}}} x {{{12/(5x-15)}}}
Once you've gotten this far, factor the 2x - 6 and the 5x - 15:
{{{(2(x - 3))/21}}} x {{{12/(5(x - 3))}}}
Now, let the (x - 3)s cancel each other out:
{{{2/21}}} x {{{12/5}}}
Cross-cancel the 21 and the 12 by a factor of 3:
{{{2/7}}} x {{{4/5}}}
Multiply outright:
{{{2/7}}} x {{{4/5}}} = {{{8/35}}}