Question 1007978
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Two fractions have denominators 3 and 4 and their sum is 1712. If the numerators are switched, the sum is 32 . Set up a linear system and solve it using elimination to determine the two numerators. (6 marks) 
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Let x and y be the numerators of the first and the second fraction.

Then you have this system of two equations in two unknowns:


{{{x/3}}} + {{{y/4}}} = 1712,

{{{x/4}}} + {{{y/3}}} = 32.


First step to simplify it is to multiply each equation by 12. You will get

4x + 3y = 1712*12

3x + 4y = 32*12.

Can you solve it yourself?
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