Question 86233
Center is (0,3) and radius is 3.

So equation of the circle is (x-0)^2 + (y-3)^2 = 3^2

==> x^2 + (y-3)^2 = 9

On further simplification,

==> x^2 + y^2 - 6y + 9 = 9

or x^2 + y^2 - 6y = 0