Question 1007562
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You need to describe the complex number *[tex \Large 8\ -\ 8i] in terms of the polar coordinates *[tex \Large r] and *[tex \Large \theta].


For *[tex \Large a\ +\ bi],


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \sqrt{a^2\ +\ b^2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \theta\ =\ \arctan\left(\frac{b}{a}\right)]


Note that the vertical axis is the imaginary axis, hence your angle is going to be in the 4th quadrant.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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