Question 1007523
if  the equation {{{-(1/2)x+3y=-3}}}, then
{{{x-intercept}}} is at ({{{x}}},{{{0}}})

so, set {{{y=0}}} and solve for {{{x}}}

{{{-(1/2)x+3*0=-3}}}

{{{-(1/2)x=-3}}}

{{{x=-3/(-1/2)}}}

{{{x=(3*2)/1}}}

{{{x=6}}}

{{{x-intercept}}} is at ({{{6}}},{{{0}}})

 and 
{{{y-intercept}}} is at ({{{0}}},{{{y}}})

so, set {{{x=0}}} and solve for {{{y}}}

{{{-(1/2)*0+3y=-3}}}

{{{3y=-3}}}

{{{y=-3/3}}}

{{{y=-1}}}


{{{y-intercept}}} is at ({{{0}}},{{{-1}}})


{{{ graph( 600, 600, -10, 10, -10, 10, (1/6)x-1) }}}