Question 1007275
A fish is being reeled in at a rate of 30cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the line and the water changing when there is 8m of line out ? 
fishing line = hypotenuse 
4m= height 
theta= angle opposite 4m and adjacent water and hypotenuse 
Hypotenuse = c
-------
Angle a = arcsin(4/c)
Differentiate implicitly
da/dt = {{{(1/sqrt(1 - (4/c)^2))*(-4/c^2)* (dc/dt)}}}
dc/dt = -0.3 m/sec
da/dt = (1/sqrt(1 – 16/64))*(-4/64)*(-0.3)
da/dt = (1/sqrt(3/4))*(1.2/64)
= sqrt(3)/80 rad/sec