Question 1007429
The numbers are {{{system(2n+1,2n+3,2n+5)}}}


Description translates to {{{(2n+1)(2n+5)=59+2(2n+3)}}}
algebra steps...
{{{highlight_green(n^2+2n-15=0)}}}


{{{(n-3)(n+5)=0}}}
The specified fact to match was POSITIVE integers, so take this solution as {{{highlight(n=3)}}}.


Evaluating the list numbers' expressions, the consecutive positive odd integers
are 7, 9, 11.