Question 86221
{{{((6x^4/2xy^3))^3}}}
ok first you want to reduce fraction as much as you can, so {{{6/2=3}}} that leaves you with 
{{{((3x^4/xy^3))^3}}} now do the same with x term since you have x on top and x on bottom so you are left with
{{{((3x^3/y^3))^3}}} now you take everything to the third power
so {{{3^3=27}}}, {{{(x^3)^3=x^9}}} and {{{(y^3)^3=x^9}}} so the answer is
{{{(27x^9)/y^9}}}