Question 1007273
Using the laws of logarithms on
ln(x+2)+lnx=ln(x+12)
we get
ln x(x+2) = ln (x+12)
x(x+2) = x+12
x^2 + 2x = x + 12
x^2 + x - 12 = 0
(x + 4)(x - 3) = 0
x = -4 or x = 3
but x cannot be -4, so
x = 3