Question 1007192
You merely plug in the values 1 and 2 in for t in the formula
{{{R(t) = 615,000/(1 + 3.6*e^(&#8722;0.044t))}}} and get
R(1) = 615,000/(1 + 3.6*e^(&#8722;0.044)) = $138,356.64
R(2) = 615,000/(1 + 3.6*e^(&#8722;0.044*2)) = $143,131.80
Then we look at what would happen to R(t) if t gets large...you can plug in 1000 for t to see that...
R(1000) = 615,000/(1 + 3.6*e^(&#8722;0.044*1000)) = almost 615,000
As you can see, the revenue approaches $615,000.