Question 1007118
let the average age of {{{8}}} men be {{{8m/8}}} 

if the average is decreased by {{{2}}} years when two of them replaced by two young boys {{{b}}}

{{{(6m+2b)/8}}}
if two of those who are replaced  are {{{22}}} and {{{28}}} old, then we have

{{{((6m + 22 + 28) / 8)- 2 = (6m + 2b) / 8}}}

{{{((6m + 50) / 8)- 2 = (6m + 2b) / 8}}}

{{{((6m + 50) / 8)-  (6m + 2b) / 8=2}}}

{{{((6m + 50) -  (6m + 2b)) / 8=2}}}

{{{(6m + 50 -  6m - 2b) =2*8}}}

{{{ 50 - 2b =16}}}

{{{ 50 - 16 =2b}}}

{{{34 =2b}}}-> age of two young boys

then average age of two boys is
{{{34/2=17}}}