Question 1007123
xy = 24 yields y = 24/x
yz = 56 yields y = 56/z


y equal to both yields 24/x = 56/z
that leads to 24z = 56x
that leads to z = 56x/24


that means that z has to be greater than x and the ratio of z to x has to be 56/24.


since 56/24 is not an integer, then x has to be a multiple of whatever makes 56/24 * x an integer.


56/24 reduces to 7/3.


x can be equal to 3,6,9,12,15,18,.....


in other words x can be a multiple of 3.


but not all multiples of 3 will work.


that's because xy has to be equal to 24.


when x = 3, y is equal to 8.
when x = 6, y is equal to 4.
when x = 9, y is not an integer.
when x = 12, y is equal to 2.
when x = 15, y is not an integer.
when x = 18, y is not an integer.
hen x = 21, y is not an integer.
when x = 24, y is equal to 1 which is not greater than 1.


the only possible values of x are 3 or 6 or 12.


when x is 3, y is 8, and z is 7 because xy = 24 and yz = 56.
you get x < z < y
that is not one of the selections.


when x is 6, y is 4 and z is 14 because 6*4 = 24 and 4*14 = 56.
you get y < x < z
that is selection B.


when x is 12, y is 2 and z is 28 because 12*2 = 24 and 2*28 = 56.
you get y < x < z
this is selection B.


i would go with selection B.