Question 1007120
<pre>

The gp is:

______, _____, 108, ____, _____,    32, _____, _____, ...


which is actually this sequence:

108/r², 108/r, 108, 108r, 108r², 108r³, 108d<sup>4</sup>, 108d<sup>5</sup>, ...

So the 6th term, 32, must equal 108r³

                    32 = 108r³
                32/108 = r³
                  8/27 = r³
                 2³/3³ = r³
                (2/3)³ = r³
                   2/3 = r

The first term is 108/r² = 108/(2/3)² = 108/(4/9) = 108(9/4) = 243

Checking the sequence, we use first term 243 and common ratio 2/3

243, 162, 108, 72, 48, 32, ...

The third term is 108 and the 6th term is 32.

Edwin</pre>