Question 1007096
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Solve the application problem

Log2 (x) = 3-log2 (x-2)
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<pre>
{{{log(2,x)}}} = {{{3}}} - {{{log(2,(x-2))}}} -----> {{{x}}} = {{{(2^3)/(x-2)}}} -----> {{{x*(x-2)}}} = {{{8}}} ----->

{{{x^2 -2x - 8}}} = {{{0}}}.

Factor it:

(x-4)*(x+2) = 0.

The roots are x = 4 and x = -2.

Negative x doesn't work due to logarithm . . . 

x = 4 works well.

<U>Answer</U>. x = 4.
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