Question 1006991
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Solve the equation for solutions over the interval [0,2pi) by first solving for the trigonometric equation. 
4sinx+6=6
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4sinx + 6 = 6.


Subtract 6 from both sides. You will get


4*sin(x) = 0, or sin(x) = 0.


The solutions of the least equations are x = 0, {{{pi/4}}}, {{{pi/2}}}, {{{3*pi/4}}}, . . . , {{{7*pi/4}}} in the interval [0, {{{2pi}}}).