Question 1006905
{{{(9x^2)^(1/2)=(y^2)^(1/2)}}}


{{{0+- 3x=0+- y}}}


Either signs are the same or they are not; the 0 was included only for site rendering.


{{{3x=0 +-y}}}
or if preferred,
{{{y=0+- 3x}}}   or  {{{x=0+- (1/3)y}}}