Question 1006819
{{{a[1]=3}}}



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{{{a[n] = 2*a[n-1]-3}}}



{{{a[2] = 2*a[2-1]-3}}}



{{{a[2] = 2*a[1]-3}}}



{{{a[2] = 2*3-3}}}



{{{a[2] = 6-3}}}



{{{a[2] = 3}}}



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{{{a[n] = 2*a[n-1]-3}}}



{{{a[3] = 2*a[3-1]-3}}}



{{{a[3] = 2*a[2]-3}}}



{{{a[3] = 2*3-3}}}



{{{a[3] = 6-3}}}



{{{a[3] = 3}}}



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{{{a[n] = 2*a[n-1]-3}}}



{{{a[4] = 2*a[4-1]-3}}}



{{{a[4] = 2*a[3]-3}}}



{{{a[4] = 2*3-3}}}



{{{a[4] = 6-3}}}



{{{a[4] = 3}}}



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{{{a[n] = 2*a[n-1]-3}}}



{{{a[5] = 2*a[5-1]-3}}}



{{{a[5] = 2*a[4]-3}}}



{{{a[5] = 2*3-3}}}



{{{a[5] = 6-3}}}



{{{a[5] = 3}}}



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It turns out that every term of this sequence is 3



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The first five terms are: <font color=red>3, 3, 3, 3, 3</font>