Question 1006797
The integers,  2n+1, 2n+3;


The basic equation formed according to description, {{{(2n+1)(2n+3)=11+2((2n+1)+(2n+3))}}}


Work the algebra.
{{{4n^2+8n+3=11+2(4n+4)}}}
{{{4n^2+8n+3=11+8n+8}}}
{{{4n^2+3-11-8=0}}}
{{{4n^2-16=0}}}
{{{n^2-4=0}}}


{{{highlight(n=-2)}}}  or  {{{highlight(n=2)}}};


The integers can be  -3 and -1;
or
5 and 7.