Question 1006688
 two cars left daisy's diner at the same time and traveled in opposite directions.
 one car traveled for 78 minutes.
 the other car traveled for 144 minutes at a rate of 5 km/h faster than the first car.
 if the faster car went twice as far as the slower car, how fast did each car travel? 
L
let s = speed of the 1st car
then
(s+5) = the speed of the 2nd car
:
Since we are using km per hr, we have convert the minutes to hrs
dist = time * speed
2nd car dist = twice 1st car dist
{{{144/60}}}*(s+5) = 2({{{78/60}}} * s)
multiply both sides by 60
144(s+5) = 2(78s) 
144s + 720 = 156s
720 = 156s - 144s
720 = 12s
s = 720/12
s = 60 km/hr speed of the 1st car
then obviously,
65 km/hr is the speed of the 2nd car
:
:
Check this by finding the actual distance each traveled
{{{144/60}}} * 65 = 156 km
{{{78/60}}} * 60 = 78 km, half as far