Question 1006528
Several cylinders are different sizes, but for each one the surface area and the volume have the same numerical value.
 If the radius and height are both integers, what is the largest volume possible? 
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Assuming the Surface area includes the ends.
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Surface area = volume
{{{(2*pi*r^2) + (2*pi*r*h) = pi*r^2*h}}}
factor out pi*r
{{{pi*r(2r + 2h) = pi*r^2*h}}}
divide both sides by pi*r
2r + 2h = rh
2r = rh - 2h
factor out h
2r = h(r-2)
Divide both sides by (r-2) and write
h = {{{(2r)/(r-2)}}}
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Looking at this simple equation, we can see that r has to be greater than 2
Try:
 r = 3, then h = 6
 r = 4, then h = 4
 r = 5, h is not an integer
 r = 6, h = 3
 no other integer solutions
Max volume: r=6; h=3; {{{pi*6^2*3}}} = 339.3 cubic units
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Check solution by finding the surface area where r=6; h=3
{{{(2*pi*r^2) + (2*pi*r*h)}}} = 339.3 sq units