Question 1006656
the perimeter of a rectangle is 18 feet. 
the width of the rectangle is seven less than the width.
find the width 
x-7 is the width and x is the length 
first solve for x which is 2(x)+2(x-7) = 18 
I know that you multiply and come out with x=5 then find the width using x-7+_____ inches
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Use W & L for clarity.
2W + 2L = 18
W = L-7
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2(L-7) + 2L = 18
4L = 32
L = 8
W = 1