Question 1006597
Look for the zeros of the denominator, the values of x which make the denominator 0.  This you
can do easily because the denominator is a quadratic expression in standard form.


The solution to  {{{4(x-5)^2-1=0}}}  will be the values of x for which the function g(x) is undefined.


{{{4(x-5)^2=1}}}
{{{(x-5)^2=1/4}}}
{{{((x-5)^2)^(1/2)=0+- 1/2}}}
{{{x-5=0+- 1/2}}}
{{{highlight(x=5+- 1/2)}}}


{{{4&1/2}}} and {{{5&1/2}}} are the values which are UNDEFINED for x in g.