Question 1006537
.
p(x) = (x-6)*(x-(7+i))*(x-(7-i)) = (x-6)*(x^2 - 14x + 50).


It is based on two theorems.


First theorem says: 
"If a polynomial with real coefficients has a complex root (the root which is complex number) 

then it has the root which is complex conjugate to the first one".


Second theorem says: 
"If a polynomial p(x) of degree n with the leading coefficient 1 at {{{x^n}}} has n roots {{{x[1]}}}, {{{x[2]}}}, . . . , {{{x[n]}}}, 

then the polynomial is p(x) = {{{(x - x[1])}}}*{{{(x - x[2])}}}* . . . *{{{(x-x[n])}}}.