Question 1006490
(63-7a^2)/(a^3-9a) = {7(9-a^2)}/{a(a^2-9)} = {7(3^2-a^2)}/{a(a^2-3^2)} = (7(3-a)(3+a)}/{a(a+3)(a-3)} = {-7(a-3)(a+3)}/{a(a-3)(a+3)} = -7/a

Ans. D) -7/a